Finite Math Examples

$\frac{3 m}{6 m^{2} + 13 m n + 6 n^{2}} + \frac{2 m}{4 m^{2} + 8 m n + 3 n^{2}}$

Step 1

Simplify each term.

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Step 1.1

Factor by grouping.

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Step 1.1.1

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 6 \cdot 6 = 36$ and whose sum is $b = 13$ .

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Step 1.1.1.1

Reorder terms.

$\frac{3 m}{6 m^{2} + 6 n^{2} + 13 m n} + \frac{2 m}{4 m^{2} + 8 m n + 3 n^{2}}$

Step 1.1.1.2

Reorder $6 n^{2}$ and $13 m n$ .

$\frac{3 m}{6 m^{2} + 13 m n + 6 n^{2}} + \frac{2 m}{4 m^{2} + 8 m n + 3 n^{2}}$

Step 1.1.1.3

Factor $13$ out of $13 m n$ .

$\frac{3 m}{6 m^{2} + 13 (m n) + 6 n^{2}} + \frac{2 m}{4 m^{2} + 8 m n + 3 n^{2}}$

Step 1.1.1.4

Rewrite $13$ as $4$ plus $9$

$\frac{3 m}{6 m^{2} + (4 + 9) (m n) + 6 n^{2}} + \frac{2 m}{4 m^{2} + 8 m n + 3 n^{2}}$

Step 1.1.1.5

Apply the distributive property.

$\frac{3 m}{6 m^{2} + 4 (m n) + 9 (m n) + 6 n^{2}} + \frac{2 m}{4 m^{2} + 8 m n + 3 n^{2}}$

Step 1.1.1.6

Move parentheses.

$\frac{3 m}{6 m^{2} + 4 m n + 9 m n + 6 n^{2}} + \frac{2 m}{4 m^{2} + 8 m n + 3 n^{2}}$

Step 1.1.2

Factor out the greatest common factor from each group.

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Step 1.1.2.1

Group the first two terms and the last two terms.

$\frac{3 m}{(6 m^{2} + 4 m n) + 9 m n + 6 n^{2}} + \frac{2 m}{4 m^{2} + 8 m n + 3 n^{2}}$

Step 1.1.2.2

Factor out the greatest common factor (GCF) from each group.

$\frac{3 m}{2 m (3 m + 2 n) + 3 n (3 m + 2 n)} + \frac{2 m}{4 m^{2} + 8 m n + 3 n^{2}}$

Step 1.1.3

Factor the polynomial by factoring out the greatest common factor, $3 m + 2 n$ .

$\frac{3 m}{(3 m + 2 n) (2 m + 3 n)} + \frac{2 m}{4 m^{2} + 8 m n + 3 n^{2}}$

Step 1.2

Factor by grouping.

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Step 1.2.1

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 4 \cdot 3 = 12$ and whose sum is $b = 8$ .

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Step 1.2.1.1

Reorder terms.

$\frac{3 m}{(3 m + 2 n) (2 m + 3 n)} + \frac{2 m}{4 m^{2} + 3 n^{2} + 8 m n}$

Step 1.2.1.2

Reorder $3 n^{2}$ and $8 m n$ .

$\frac{3 m}{(3 m + 2 n) (2 m + 3 n)} + \frac{2 m}{4 m^{2} + 8 m n + 3 n^{2}}$

Step 1.2.1.3

Factor $8$ out of $8 m n$ .

$\frac{3 m}{(3 m + 2 n) (2 m + 3 n)} + \frac{2 m}{4 m^{2} + 8 (m n) + 3 n^{2}}$

Step 1.2.1.4

Rewrite $8$ as $2$ plus $6$

$\frac{3 m}{(3 m + 2 n) (2 m + 3 n)} + \frac{2 m}{4 m^{2} + (2 + 6) (m n) + 3 n^{2}}$

Step 1.2.1.5

Apply the distributive property.

$\frac{3 m}{(3 m + 2 n) (2 m + 3 n)} + \frac{2 m}{4 m^{2} + 2 (m n) + 6 (m n) + 3 n^{2}}$

Step 1.2.1.6

Move parentheses.

$\frac{3 m}{(3 m + 2 n) (2 m + 3 n)} + \frac{2 m}{4 m^{2} + 2 m n + 6 m n + 3 n^{2}}$

Step 1.2.2

Factor out the greatest common factor from each group.

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Step 1.2.2.1

Group the first two terms and the last two terms.

$\frac{3 m}{(3 m + 2 n) (2 m + 3 n)} + \frac{2 m}{(4 m^{2} + 2 m n) + 6 m n + 3 n^{2}}$

Step 1.2.2.2

Factor out the greatest common factor (GCF) from each group.

$\frac{3 m}{(3 m + 2 n) (2 m + 3 n)} + \frac{2 m}{2 m (2 m + n) + 3 n (2 m + n)}$

Step 1.2.3

Factor the polynomial by factoring out the greatest common factor, $2 m + n$ .

$\frac{3 m}{(3 m + 2 n) (2 m + 3 n)} + \frac{2 m}{(2 m + n) (2 m + 3 n)}$

Step 2

To write $\frac{3 m}{(3 m + 2 n) (2 m + 3 n)}$ as a fraction with a common denominator, multiply by $\frac{2 m + n}{2 m + n}$ .

$\frac{3 m}{(3 m + 2 n) (2 m + 3 n)} \cdot \frac{2 m + n}{2 m + n} + \frac{2 m}{(2 m + n) (2 m + 3 n)}$

Step 3

To write $\frac{2 m}{(2 m + n) (2 m + 3 n)}$ as a fraction with a common denominator, multiply by $\frac{3 m + 2 n}{3 m + 2 n}$ .

$\frac{3 m}{(3 m + 2 n) (2 m + 3 n)} \cdot \frac{2 m + n}{2 m + n} + \frac{2 m}{(2 m + n) (2 m + 3 n)} \cdot \frac{3 m + 2 n}{3 m + 2 n}$

Step 4

Write each expression with a common denominator of $(3 m + 2 n) (2 m + 3 n) (2 m + n)$ , by multiplying each by an appropriate factor of $1$ .

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Step 4.1

Multiply $\frac{3 m}{(3 m + 2 n) (2 m + 3 n)}$ by $\frac{2 m + n}{2 m + n}$ .

$\frac{3 m (2 m + n)}{(3 m + 2 n) (2 m + 3 n) (2 m + n)} + \frac{2 m}{(2 m + n) (2 m + 3 n)} \cdot \frac{3 m + 2 n}{3 m + 2 n}$

Step 4.2

Multiply $\frac{2 m}{(2 m + n) (2 m + 3 n)}$ by $\frac{3 m + 2 n}{3 m + 2 n}$ .

$\frac{3 m (2 m + n)}{(3 m + 2 n) (2 m + 3 n) (2 m + n)} + \frac{2 m (3 m + 2 n)}{(2 m + n) (2 m + 3 n) (3 m + 2 n)}$

Step 4.3

Reorder the factors of $(3 m + 2 n) (2 m + 3 n) (2 m + n)$ .

$\frac{3 m (2 m + n)}{(2 m + 3 n) (2 m + n) (3 m + 2 n)} + \frac{2 m (3 m + 2 n)}{(2 m + n) (2 m + 3 n) (3 m + 2 n)}$

Step 4.4

Reorder the factors of $(2 m + n) (2 m + 3 n) (3 m + 2 n)$ .

$\frac{3 m (2 m + n)}{(2 m + 3 n) (2 m + n) (3 m + 2 n)} + \frac{2 m (3 m + 2 n)}{(2 m + 3 n) (2 m + n) (3 m + 2 n)}$

Step 5

Combine the numerators over the common denominator.

$\frac{3 m (2 m + n) + 2 m (3 m + 2 n)}{(2 m + 3 n) (2 m + n) (3 m + 2 n)}$

Step 6

Simplify the numerator.

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Step 6.1

Factor $m$ out of $3 m (2 m + n) + 2 m (3 m + 2 n)$ .

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Step 6.1.1

Factor $m$ out of $3 m (2 m + n)$ .

$\frac{m (3 (2 m + n)) + 2 m (3 m + 2 n)}{(2 m + 3 n) (2 m + n) (3 m + 2 n)}$

Step 6.1.2

Factor $m$ out of $2 m (3 m + 2 n)$ .

$\frac{m (3 (2 m + n)) + m (2 (3 m + 2 n))}{(2 m + 3 n) (2 m + n) (3 m + 2 n)}$

Step 6.1.3

Factor $m$ out of $m (3 (2 m + n)) + m (2 (3 m + 2 n))$ .

$\frac{m (3 (2 m + n) + 2 (3 m + 2 n))}{(2 m + 3 n) (2 m + n) (3 m + 2 n)}$

Step 6.2

Apply the distributive property.

$\frac{m (3 (2 m) + 3 n + 2 (3 m + 2 n))}{(2 m + 3 n) (2 m + n) (3 m + 2 n)}$

Step 6.3

Multiply $2$ by $3$ .

$\frac{m (6 m + 3 n + 2 (3 m + 2 n))}{(2 m + 3 n) (2 m + n) (3 m + 2 n)}$

Step 6.4

Apply the distributive property.

$\frac{m (6 m + 3 n + 2 (3 m) + 2 (2 n))}{(2 m + 3 n) (2 m + n) (3 m + 2 n)}$

Step 6.5

Multiply $3$ by $2$ .

$\frac{m (6 m + 3 n + 6 m + 2 (2 n))}{(2 m + 3 n) (2 m + n) (3 m + 2 n)}$

Step 6.6

Multiply $2$ by $2$ .

$\frac{m (6 m + 3 n + 6 m + 4 n)}{(2 m + 3 n) (2 m + n) (3 m + 2 n)}$

Step 6.7

Add $6 m$ and $6 m$ .

$\frac{m (12 m + 3 n + 4 n)}{(2 m + 3 n) (2 m + n) (3 m + 2 n)}$

Step 6.8

Add $3 n$ and $4 n$ .

$\frac{m (12 m + 7 n)}{(2 m + 3 n) (2 m + n) (3 m + 2 n)}$